Ne funkcionise definisanje promenljive kod skripte za pretraguCode:
<h2>Search</h2>
<form name="search" method="post" action="Osnovna pretraga.php">
Seach for: <input type="text" name="find" value="yes"/> in
<Select NAME="field">
<Option VALUE="fname">First Name</option>
<Option VALUE="lname">Last Name</option>
<Option VALUE="info">Profile</option>
</Select>
<input type="hidden" name="searching" value="yes" />
<input type="submit" name="search" value="Search" />
</form>
<h2>Search</h2>
<form name="search" method="post" action="Osnovna pretraga.php">
Seach for: <input type="text" name="find" value="yes"/> in
<Select NAME="field">
<Option VALUE="fname">First Name</option>
<Option VALUE="lname">Last Name</option>
<Option VALUE="info">Profile</option>
</Select>
<input type="hidden" name="searching" value="yes" />
<input type="submit" name="search" value="Search" />
</form>
PHP
Code:
<?
//This is only displayed if they have submitted the form
if ($searching =="yes") <---------------- OVO JE 12 LINIJA KODA
{
echo "<h2>Results</h2><p>";
//If they did not enter a search term we give them an error
if ($find == "")
{
echo "<p>You forgot to enter a search term";
exit;
}
// Otherwise we connect to our Database
mysql_connect("localhost", "root", "") or die(mysql_error());
mysql_select_db("Pretraga") or die(mysql_error());
// Treba nekako definisati promenljivu searching,mozda ovako nekako $searching=$_POST['searching'];
// We preform a bit of filtering
$find = strtoupper($find);
$find = strip_tags($find);
$find = trim ($find);
//Now we search for our search term, in the field the user specified
$data = mysql_query("SELECT * FROM users WHERE upper($field) LIKE'%$find%'");
//And we display the results
while($result = mysql_fetch_array( $data ))
{
echo $result['fname'];
echo " ";
echo $result['lname'];
echo "<br>";
echo $result['info'];
echo "<br>";
echo "<br>";
}
//This counts the number or results - and if there wasn't any it gives them a little message explaining that
$anymatches=mysql_num_rows($data);
if ($anymatches == 0)
{
echo "Sorry, but we can not find an entry to match your query<br><br>";
}
//And we remind them what they searched for
echo "<b>Searched For:</b> " .$find;
}
?>
<?
//This is only displayed if they have submitted the form
if ($searching =="yes") <---------------- OVO JE 12 LINIJA KODA
{
echo "<h2>Results</h2><p>";
//If they did not enter a search term we give them an error
if ($find == "")
{
echo "<p>You forgot to enter a search term";
exit;
}
// Otherwise we connect to our Database
mysql_connect("localhost", "root", "") or die(mysql_error());
mysql_select_db("Pretraga") or die(mysql_error());
// Treba nekako definisati promenljivu searching,mozda ovako nekako $searching=$_POST['searching'];
// We preform a bit of filtering
$find = strtoupper($find);
$find = strip_tags($find);
$find = trim ($find);
//Now we search for our search term, in the field the user specified
$data = mysql_query("SELECT * FROM users WHERE upper($field) LIKE'%$find%'");
//And we display the results
while($result = mysql_fetch_array( $data ))
{
echo $result['fname'];
echo " ";
echo $result['lname'];
echo "<br>";
echo $result['info'];
echo "<br>";
echo "<br>";
}
//This counts the number or results - and if there wasn't any it gives them a little message explaining that
$anymatches=mysql_num_rows($data);
if ($anymatches == 0)
{
echo "Sorry, but we can not find an entry to match your query<br><br>";
}
//And we remind them what they searched for
echo "<b>Searched For:</b> " .$find;
}
?>
Greska koja mi se javlja glasi Notice: Undefined variable: searching in C:\xampp\nastavak putanje\Search.php on line 12
Ista greska mi se javila u jednoj prethodnoj skripti i resio sam je ubacivanjem ove linije koda koja bi u ovom slucaju trebala da izgleda valjda ovako $searching=$_POST['searching']; .
Mislio sam da se ovako resava problem sa ovom greskom ali sam izgleda pogresio.
Sta treba da uradim da bi se resio ove greske?
Hvala unapred.
