Ako uzimas $ime $komentar .... sa istog servera na koji se kacis uz pomoc FTP-a ovo ti je dovoljno. Zato sto je to isti server pa ti netreba ftp
Code:
$Ime = $_POST['Ime'];
$komentar = $_POST['komentar'];
$ip = getenv("REMOTE_ADDR");
$adddate = date("D M d, Y g:i a");
$file = "test.txt"
$content = "Ime : $ime, komentar : $komentar, ip : $ip, Date : $adddate \n";
$handle = fopen($file, 'a');
fwrite($handle, $content);
fclose($handle);
A ako sa tog sajta saljes podatke na neki svoj FTP server onda ovako
Code:
$Ime = $_POST['Ime'];
$komentar = $_POST['komentar'];
$ip = getenv("REMOTE_ADDR");
$adddate = date("D M d, Y g:i a");
$file = "test.txt";
$content = "Ime : $ime, komentar : $komentar, ip : $ip, Date : $adddate \n";
$handle = fopen($file, 'a');
fwrite($handle, $content);
fclose($handle);
$destination_file = "test/test.txt"; // Destinacija fajla koji treba da se snimi na ftp server
$source_file = $file;
$ftp_server = ""; // ftp server
$ftp_user_name = ""; // username
$ftp_user_pass = ""; // i password
$conn_id = ftp_connect($ftp_server);
$login_result = ftp_login($conn_id, $ftp_user_name, $ftp_user_pass);
if ((!$conn_id) || (!$login_result)) {
echo "FTP connection has failed!";
echo "Attempted to connect to $ftp_server for user $ftp_user_name";
exit;
} else {
echo "Connected to $ftp_server, for user $ftp_user_name";
}
$upload = ftp_put($conn_id, $destination_file, $source_file, FTP_BINARY);
if (!$upload) {
echo "FTP upload has failed!";
} else {
echo "Uploaded $source_file to $ftp_server as $destination_file";
}
ftp_close($conn_id);
Pomoc sa uplodovanjem podataka na FTP ako je moguce
