Pomoc oko <chksum> := <chksum> XOR <byte>.

Example:
START COMMAND BODY CHECKSUM END
ESC P 2 bytes ASCIIcodes 2 bytes ESC \
$l 1111* BDh
1Bh, 50h 24h, 6Ch 31h, 31h, 31h, 31h, 0Ah 42h, 44h 1Bh, 5Ch

Algorithm of checksum
These two bytes are hexadecimal digits representing the checksum of the whole sequence
(COMMAND+DATA) counted as shown below.
Initial value is 255 (FFh)
<chksum> := 255;
And with every byte after ESC P sequence checksum is modified
<chksum> := <chksum> XOR <byte>.
Then <chksum> is translated into 2 hexadecimal digits represented in ASCII codes.


Nisam upucen u ovo ali bi mi bilo od velikog znacaja....

uzmes win. calculator selektujes Hex i Byte mod pa kucas 1B xor 50 = 4B pa onda 4B xor 24 = 6F i tako do kraja
xor funkcija znaci exclusiv or tj ili jedan ili drugi ali ne oba tj 0+0=0 1+0=1 0+1=1 1+1=0

**11011 1Bh
1010000 50h
--------------------- xor
1001011 4Bh

ovu funkciju podrzavaju svi prog jezici

Shvatio sam ESC P, da li mozete da mi deteljno opisete celu komandu postupno...

Example:

START:
ESC P,
Comand: $I,
Body(ASCII): 1111*,
CHECKSUM: BD,
End: ESC \


ovo je nacin:


Algorithm of checksum
These two bytes are hexadecimal digits representing the checksum of the whole sequence
(COMMAND+DATA) counted as shown below.
Initial value is 255 (FFh)
<chksum> := 255;
And with every byte after ESC P sequence checksum is modified
<chksum> := <chksum> XOR <byte>.
Then <chksum> is translated into 2 hexadecimal digits represented in ASCII codes.



Hvala unapred, puno....

nije mi jasan kod koji si dao
i ja imam probl. sa in out kommandama asm

Skini ovaj pdf tu je to sto mi treba....

http://www.posnet.com.pl/files/1471/ProtSRv16.pdf

mmmmmm
ovo je protokol koliko vidim za citanje reg. kase, veliki zalogaj, radio sam nesto slicno komunikacija PC-omron termo reguul. , ne znam kojim bi ti progr. jezikom ovo radio i koliko imaas iskustva, ima li ttu kakve ekonomske racunice i ako si zaintersovan mozemo na pp ili mail
pozzzzz