Pomoc
13.05.2003. u 22:32 · pre 285 meseci
#1
Evo zaglavio sam kod ovog trigonometrijskog zadatka (II godina Tesle):
#Ovo je resenje
sin(x) + sin(y)=a
cos(x) + cos(y)=b
-----------------
(sin(x) + sin (y)) / (cos(x) + cos(y)) =
(2sin((x+y) / 2) cos ((x-y) / 2)) / (2cos((x+y) / 2) cos ((x-y) / 2))=
tg ((x+y) / 2) = a/b
#Odavde je postalo nejasno
sin (x+y) = (2tg((x+y)/2)) / (1+sqr(tg ((x+y)/2)))
#Treba da nadjem koliko je sin (x+y) u zadatku
#Ovo je resenje
sin(x) + sin(y)=a
cos(x) + cos(y)=b
-----------------
(sin(x) + sin (y)) / (cos(x) + cos(y)) =
(2sin((x+y) / 2) cos ((x-y) / 2)) / (2cos((x+y) / 2) cos ((x-y) / 2))=
tg ((x+y) / 2) = a/b
#Odavde je postalo nejasno
sin (x+y) = (2tg((x+y)/2)) / (1+sqr(tg ((x+y)/2)))
#Treba da nadjem koliko je sin (x+y) u zadatku
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