Problem:
A school play ran for two nights, with audiences totaling 1390 adults and students. They paid $4285 for admission. One adult ticket cost $4.00 and one student ticket cost $2.50. The ratio of adults to students was 3: 5 on the first night and 2: 3 on the second night. How many students attended each night?
X= # of adults
Y= # of students
x + y =1390
4x + 2.5y =4285
4x + 4y =5560
4x + 2.5y =4285
1.5y =1275
y = 850
x + 850 =1390 - 850
- 850
X = 540
540 adults and 850 students...
X= # of adults on the first day
Y= # of students on the first day
x/y = 3/5
540 - x / 850 – y = 2/3
Kako dalje, ako moze pomoc?
07.10.2007. u 23:15
Daniel011 Beograd
Član broj: 76088 Poruke: 1007 *.dynamic.sbb.co.yu.
Oh hvala, ali zapravo sam *resila.
I htela sam da pitam, jer imam probleme sa basicnom aglebrom, jer znas neki site koji moze da pomogne s tim.
I isto, ako moze, da objasnis koji code ste koristili da napisete fractions tako...
hvala.
08.10.2007. u 18:24
Daniel011 Beograd
Član broj: 76088 Poruke: 1007 *.dynamic.sbb.co.yu.